@femio009,
What is the time for the test in PHC tomorrow. I have to be there
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@femio009,
What is the time for the test in PHC tomorrow. I have to be there
Seriously,I don't know why I was not invited.
for those taking the test tomorrow in portharcourt, What is the time for the test.
Please respond I missed mine today
the test was okay. wrote mine in cham city abj. questions aint so hard buh the verbal reasonin is filled with big vocabs. try study dictionary well oh. wish all writin 2mao all d best
already @ chams city lagos,
is there any naijahotjobers there?
All d best man!
i sincerely hope i move on to the next stage cos i really prayed hard for this upliftment.
So... What next?...
functional test
oral interview
Assessment center
@ pweetysis
I pray for ur hope to become a reality in Jesus name
Was scheduled 4d test yest but couldn't make it bcos was out of land..does any1 knw if der wil be anoda reschedule test next weekend bcos I wil b available...
Was scheduled 4d test yest but couldn't make it bcos was out of land..does any1 knw if der wil be anoda reschedule test next weekend bcos I wil b available...
just staying hopeful..............
Thanks @ Diketron. I just hope its not too late to do that.
Hi guyz, does anyone know whether dragnet is still sending invitation for addax aptitude test?
amen Maestrob. Amen!!!
Was any Elect/Elect graduate invited for this addax test?
@MUC, yeah. I studied Electrical Engineering (2.1) and I was invited for the aptitude test.
I hope to hear from Addax. ( Insha Allah)
their test is far better than Chams/Dragnet. I prefer the companies to come along with their own questions to Chams than using the dragnet GSE that some people still get expo and they can not bring new sets of question which will be totally different from the previous.
Regards
@Agent001, i agree with you, i prefer the coys come up wit their questions than allow chams/dragnet give DeJa Vu questions. God help me ohh i need to move to the next stage .
when d alerts go come nau? That's very important....o; bcos I spent so much on that trip.
Ma broda, d alert is equaly v.important. Waitd al day.wetin dey hapen nw
Ma broda, d alert is equaly v.important. Waitd al day.wetin dey hapen nw. Les i forget to expres my sincere thanx to all esp ctr07 for d perfect descriptn of cham city route 4rm ib. It was just as u said.one love people. Wish u al and myself God favour
alert! Alert!! Alert!!! Anybody with info on when dey will be paying pls. And how much are we expecting.
does any body know how much we wud be getting as transport reimbursement and when dey wud be paying the reimbursements? is it a fixed amount or like shell, it depends on location?
Hi guys.. pls since learning is a continuous process; can any1 remember the question on cats & mice - something like if a certain amount of cats catch equal no. of cats totalling 999199 (i think), if the no. of cats are less than mice. how many mice did each cat catch.. pls, not too sure of d details again, any1 that remembers & can solve it, should pls help out.. thanks ..
@bonethugs.
my brother dat cat and mice thing no funny at all. I look d tin sote, it made me feel like i be olodo. It looks simple but it's complex.
learning is a continuous process like he said,so if u have an idea,pls post it
u neva can tell who will be needing it
A Cat can only catch one Mouse at a time, even if they(Mice) are rained down from the sky... I think the answer is one, except your question is incomplete.
@bonethugs89, there is 991 in the options?
@ justice59, yea i think there's was 991 & 691.. i randomly picked 691 since it was the least among the options ....
No. of cats = x(say)
Therefore, no. of mice killed by each cat = 999919/x (since, they killed equal no. of mice)
Now, given that
(999919/x) is greater than x, i.e
999919/x > x, implies x*x<999919
Therefore, x < 999.95(approx). Now, the only no. which is nearest to but less than 999.95 and is a factor of 999919 is 991.
Thus, x = 991 and no. of mice = 999919/991 = 1009.
Ans=991..
(From one site thru google search)
Here is anoda way to look at it-
Observing the num 999919 which is the total num of rats being eaten..we can write it as
(1000000-81) = (1000^2-9^2) = (1000+9)(1000-9) = (1009)(991)
so total num of rats killed =(1009)(991)
and given that each cat kills more num of rats than the total num of cats
hence each cat kills 1009 num of rats
and there are 991 num of cats.
(No be me solve am oh.. )
@krimboy THANKS SO MUCH... I ve been struggling with it since Saturday ... u r d best man..
medicine after death. But let me share my idea: 9999999 rats approx. 1milion rats, since no calculator, u can easily knw d square root to b 1000 since they killed equal nos. Nd bcos there are more rats than cats, d closest is 991
one thing I've learnt abt aptitude test is to choose d closest answer to d solution u got from solving d problem. Guys hw did see the goat tied to one corner of 12m square area. That was very logical questn.
na hia una wan dey show una local talent? D test nor rish una do? Abeg if una nor get useful info make una park well joor.